September 8, 200322 yr If we look solely at the gamelog which is the simplest measure to use: http://baseball.espn.go.com/mlb/boxscore?g...ameId=230907104 Batting HR: F Thomas (39, 7th inning off D Baez 2 on, 2 Out); P Konerko (18, 8th inning off D Lee 1 on, 1 Out) RBI: M Ordonez (85), C Lee (98), F Thomas 3 (93), P Konerko 2 (65) S: R Alomar, S Alomar Jr SF: C Lee 2-out RBI: F Thomas Runners left in scoring position, 2 out- R Alomar 1, P Konerko 1, M Ordonez 1 Team LOB: 7 Baserunning CS: M Ordonez (5, 2nd base by C Lee/V Martinez) Can we determine a PTC from this? + Pts: HR: (2*HR) Thomas = 2 Koney = 2 RBI:(1*RBI) Thomas = 3 Koney = 2 Maggs = 1 Lee = 1 2-out RBI: (1*RBI) Thomas = 1 - Pts: all -1 PT RON,2 outs: Koney = -1 CS: Maggs = -1 Thomas should win the hitters PTC 6-3 over Koney. If the SOX get shut out, then you can look at H, & AB. But otherwise, it should be the players driving in runs that get the most weight. Similarly on the PITCHING side: IP H R ER BB SO HR PC-ST ERA D Wright 5 5 2 2 1 4 2 75-47 5.42 K Wunsch 1 0 0 0 0 1 0 8-6 1.74 S Sullivan 1/3 1 1 1 1 0 0 15-7 6.35 S Schow 2/3 0 0 0 1 1 0 13-4 4.85 D Marte 1 1 0 0 0 3 0 17-10 1.66 T Gordon 1 0 0 0 0 2 0 8-7 3.33 I like ST/(R+1) as the winning PTC measure: (ST = strikes, R = runs scored) Wright = 16 Wunsch = 6 Sullivan = 3.5 Schow = 4 Marte = 10 Gordon = 7 After all hits are only counted as strikes. Now if you want only 1 PTC then for a Pitcher to win he must have a score > 3*(highest hitter) Thomas wins the PTC 18-16 over Wright. Proof: Wright needed just 10 more ST's to win. That would have left him with 6ip, 2r, 57ST's I think that was worthy of the win.
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.